# How much will 101,3 kPa in mm.rt. post. Or explain the principle of translation!

How much will 101,3 kPa in mm.rt. post. Or explain the principle of translation!

- Wow, you can break your brains! )))
- no
- pressure in Pascals = (density of mercury in kg / m3 = 13600) * (on the height of the column in millimeters) * 9.81 / 1000
sorry, sealed ... now correctly:

respectively, the pressure in mmHg = 1000 * (pressure in Pascals) / (density of mercury) / 9.81in your case, it turns out 101.3 kPa = 759.26 mm Hg. Art.

understandably? - the pressure is equal to the product of the density of the liquid by the acceleration of gravity and the height of the column. 1Pa = 1 N / m 2, density of mercury 13600 kg / m3, g = 9.81m / s ^ 2

in this case 101300: 9,81: 13600 = 0,76 mr. = 759 mmHg - Pascal (designation: Pa, Pa) unit of measurement of pressure (mechanical stress) in the SI system.

Pascal is equal to the pressure (mechanical stress) caused by a force equal to one Newton, evenly distributed over a normal surface area of one square meter.

The unit is named after the French physicist and mathematician Blaise Pascal.

Normal atmospheric pressure is considered to be equal to 760 mm of mercury, or 101325 Pa. Hence the translation of pascal in mm. gt; Art. is carried out at a simple ratio: 1000Pa = 1 kPa and corresponds approximately = 7.5 mm Hg. Art. - 1 mmHg item = 13600 * 0.001 * 9.8 = 133,28 Pa

101300 Pa = 760 mm Hg. Art.